Question

find the zeroes of the Polynomial P {x] = x²-2x-8
and verify the relation between the zeroes and the
coefficiens​

Answer 1

Answer:

Step-by-step explanation:

x²-2x-8=0

a=1, b=-2, c=-8

x²-x(4-2)-8=0

x²-4x+2x-8=0

x(x-4)+2(x-4)=0

(x+2) or (x-4)=0

x+2=0 x=-2

x-4=0 x=4

α=-2 β=4

αβ=c/a

-2×4=--8/1

-8=-8

LHS=RHS  hence verified

α+β=-b/a

-2+4=-(-2)/1

2=2/1

2=2

LHS=RHS HENCE VERIFIED

PLS MARK ME AS BRAINLIEST IF YOU LIKED THE EXPLANATION OF THE ANSWER AND IF IT IS CORRECT