Question

Find the zeroes of the polynomial p(x)=x²-2x-8and verify the relationship between zeroes and coefficents

Answer 1

Step-by-step explanation:

x² - 2x - 8

= x² - 4x + 2x - 8

= X ( x - 4) + 2 ( X - 4)

= (X - 4) (X + 2)

= X = 4 , X = -2

α = 4 , β = -2

• Relationship b/w zeros and coefficient

1. Sum = α + β = - b /a

= 4 + (-2) = - (-2)/ 1

= 4 - 2 = 2

= 2 = 2

2. Product = αβ = c / a

= 4 × -2 = - 8 / 1

= - 8 = - 8