Question

Find the zeroes of the Polynomial
P(x) : x² - 3x + 4
​

Answer 1

Ans. P(x)=x^2 - 3x + 4

= x^2+ x - 4x + 4

= x(x-1)-4(x-1)

= (x-1)(x-4)

Zeroes of P(x) = x-1= 0

x= 1

x-4= 0

x=4

Zeroes of the polynomial P(x) are 1 and 4.

Answer 2

★Answer:-

★Given:-

The polynomial is x² - 3x + 4

★To Find :-

The Zeroes of the polynomial.

★Solution:-

⇒p(x ) = x² - 3x + 4

⇒p(x) = 0

⇒x² -3x + 4 = 0

Doing Middle term ,

⇒x² + (4 - 1 )x - 4 = 0

⇒x² + 4x - x - 4 = 0

⇒x ( x + 4 ) -1 ( x + 4 ) = 0

⇒( x +4 ) ( x - 1) =0

Either, ..

☆ X + 4 = 0

↦x = -4

Or,...

☆ x -1 = 0

↦x = 1

$\therefore{x = -4 \: Or \:x = 1}$

Hence, Zeroes of the polynomial are -4 , 1.