Question

Find the zeroes of the polynomial : p(x) = x² - 9​

Answer 1

$\huge\sf\red{\underline{\underline{Given}}}\::$

$\begin{cases}\sf\gray{{x}^{2} \ - \ 9 \ = \ 0}\end{cases}$

$\huge\sf\blue{\underline{\underline{To\:Find}}}\::$

$\begin{cases}\sf\gray{zeroes \: of \: polynomial}\end{cases}$

$\huge\sf\pink{\underline{\underline{Solution}}}\::$

${\bold{\underline{\orange{As \: we \: know \: that}}}} \\\\ \mapsto\:\:{\sf{\purple{ {x}^{2} - 9 = 0}}} \\ \\ \mapsto\:\:{\sf{\green{{x}^{2} = 9}}} \\ \\ \mapsto\:\:{\sf{\purple{ x = \sqrt{9}}}} \\ \\ \mapsto\:\:{\sf{\purple{ x = \pm3}}} \\ \\ {\bold{\underline{\orange{Alternate \: method }}}} \\ \\ \mapsto\:\:{\sf{\purple{ {x}^{2} - 9 = 0}}} \\ \\ {\sf{\green{\bullet\:\: \: a = 1 \: \: \: \: \: b = 0 \: \: \: \: \: c = - 9}}}\\ \\ \mapsto\:\:{\sf{\purple{ x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}}}} \\ \\ \mapsto\:\:{\sf{\green{ x = \frac{ - 0 \pm \sqrt{ {0}^{2} - 4 \times 1 \times ( - 9) } }{2 \times 1}}}} \\ \\ \mapsto\:\:{\sf{\purple{ x = \frac{ \pm \sqrt{36} }{2}}}} \\ \\ \mapsto\:\:{\sf{\green{ x = \frac{ \pm6}{2} }}} \\ \\ \star\:{\boxed{\sf{\red{ x = \pm 3}}}}$

Answer 2

$\huge{\underline{\tt{QUESTION:-}}}$

Find the zeroes of the polynomial : p(x) = x² - 9​

$\huge{\underline{\tt{ANSWER:-}}}$

Refer to the attachment !