Find the zeroes of the polynomial p(x)=x³-2x²-x+2
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4
X=1
p(1)=1^3-2(1)^2-1+2
=1-2(1)-1+2
=1-2-1+2
=3-3
=0
Therefore,X=1 is the zero of p(X)
p(1)=1^3-2(1)^2-1+2
=1-2(1)-1+2
=1-2-1+2
=3-3
=0
Therefore,X=1 is the zero of p(X)
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