Question

Find the zeroes of the polynomial S² -(1+2√2)s + √28 by factorisation method and verify the relations between the zeroes and the coefficients of the polynomial.​

Answer 1

Answer:

Given quadratic polynomial is 2s2−(1+22)s+2

=2s2−s−22s+2

=s(2s−1)−2(2s−1)

=(2s−1)(s−2)

s=21 and s=2

The relationship between the zeroes and their coefficient,

Sum of the zeroes=−coefficient of s2coefficient of s

                              =−(2−(1+22))

                              =21+22

Also sum of the zeroes=21+2

                                        =21+22     

Product of the zeroes

Answer 2

Step-by-step explanation:

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