Question

Find the zeroes of the polynomial

$2x {}^{2} \: + \: 5x \: - \: 12$
Verify the relationship between zeroes and co efficient

Answer 1

HOLA

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$2x {}^{2} \: + \: 5x \: - \: 12 \\ 2x {}^{2} \: + \: 8x \: - \: 3 \: - \: 12 \\ 2 \: ( \: x \: \: - \: 4) \: - \: 3 \: (x \: + \: 4) \\ (x \: - \: 4 \: ) \: - \: (2x \: + \: 3) \: \\ x \: = \: - 4 \: \: x \: = \: \: \frac{3}{2}$
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$\alpha \: + \: \beta \: = \: - 4 \: + \: \frac{3}{2} = \: \frac{ - 5}{2} \\ \\ \alpha \beta \: \: = \: - 4 \: \times \: \frac{3}{2} = \: \frac{ - 12}{2}$
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$hope \: u \: understand$