Question

Find the Zeroes of the Polynomial :
${a}^{2} + 7a + 10$
​

Answer 1

$\:\: \underline{\underline{\bf{\large\mathfrak{~~solution~~}}}}$

$a {}^{2} + 7a + 10 \\ = a {}^{2} + 5a + 2a + 10 \\ = a(a + 5) + 2(a + 5) \\ = (a + 2)(a + 5) \\ \\ the \: zeroes \: are \: a = - 5 \: \: and \: - 2$

Answer 2

$\red {\huge {\underline{ \frak{Your \: answEr : }}}}$

$\large\mapsto \tt{ {a}^{2} + 7a + 10 = 0}$

$\large\mapsto \tt{ {a}^{2} + 5a + 2a + 10 = 0}$

$\large\mapsto \tt{a(a + 5) + 2(a + 5) = 0}$

$\large\mapsto \tt{(a + 2)(a + 5) = 0}$

$\large\mapsto \tt{(a + 2) = 0 \: or \: (a + 5) = 0}$

$\purple{\huge\mapsto \boxed{\tt{a = - 2 \: or \: - 5}}}$

$\therefore$ Zeroes of the Polynomial are -2 and -5.