find the zeroes of the polynomial
![p(x) = (x - 2) {}^{2} - (x + 2) {}^{2} p(x) = (x - 2) {}^{2} - (x + 2) {}^{2}](https://tex.z-dn.net/?f=p%28x%29+%3D+%28x+-+2%29+%7B%7D%5E%7B2%7D++-+%28x+%2B+2%29+%7B%7D%5E%7B2%7D+)
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Here is the solution.
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(x-2)²-(x+2)²
x²+2²-2*x*2-x²+2²+2*x*2
x²+4-4x-x²+4+4x
=8
x²+2²-2*x*2-x²+2²+2*x*2
x²+4-4x-x²+4+4x
=8
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