Question

Find the zeroes of the polynomial $x^{2} = 4\sqrt{3} -15$

Answer 1

$\underline{ \large\tt\red{correct \: question}} : -$
Find the zeroes of the polynomial $x^{2} = 4\sqrt{3}x + 15$.

$\underline{\large\tt\green{correct \: answer}} : -$

We have,

$\qquad \ \ {x}^{2} = 4 \sqrt{3}x + 15 \\ \\ \implies {x}^{2} - 4 \sqrt{3} x - 15 = 0 \\ \\ \implies {x}^{2} - (5 - 1) \sqrt{3} x - 15 = 0 \\ \\ \implies {x}^{2} - 5 \sqrt{3} x + \sqrt{3} x - 15 = 0 \\ \\ \implies x(x - 5 \sqrt{3} ) + \sqrt{3} (x - 5 \sqrt{3} ) = 0 \\ \\ \implies(x - 5 \sqrt{3} )(x + \sqrt{3} ) = 0 \\ \\ \implies x - 5 \sqrt{3} = 0 \ \boxed{or} \ x + \sqrt{3} = 0 \\ \\ \implies x = 5 \sqrt{3} \qquad \boxed{or} \ \ \ x = - \sqrt{3}$

$\mid \underline{\underline{\LARGE\bf\green{Brainliest \: Answer}}}\mid$