Question

Find the zeroes of the polynomial

$x {}^{2} \: + \: 7x \: + \: 12$

Answer 1

ALOHA , SAT SRI AKAL , NAMASTE....My frnd ☺☺
Here is ur answer ⬇️
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▶️x^2 + 7x + 12 =0
x^2 + 4x+3x + 12 = 0
x(x+4) + 3(x+4) =0
(x+3) (x+4) = 0
x = -3 , x = -4

So , The zeroes of the polynomial are -3 & - 4....
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HOPE IT HELPS U✌✌

Answer 2

HOLA

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$x {}^{2} \: + \: 7x \: + \: 12 \\ \\ x {}^{2} + \: 4x \: - \: 3x \: + \: 12 \\ \\ x( \: x \: + \: 4 \: ) \: - \: 3 \: ( \: x \: + \: 4) \\ \\ ( \: x \: + \: 4 \: ) \: - \: ( \: x \: + \: \: 3 \: ) \\ \\ \\ x \: = \: - 4 \: \: x \: = \: - 3$
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Zeroes are - 4 , - 3

HOPE U UNDERSTAND ☺☺