Question

find the zeroes of the polynomial (x+1)(x-3)(x-2)


(a) 0,2,3

(b) 0,1,-2

(c) -1,3,2

(d) none of these

Other:​

Answer 1

Answer:

option c

Step-by-step explanation:

if you try to put the values, you will find that one of the terms is coming out to be zero, and anything multiplied with 0 is 0.

hope it helps!

Answer 2

Answer:

Ans is option (c) Zeros of the polynomial are alpha and beeta according to this we can solve