Question

Find the zeroes of the polynomial (x – 2)2
+ 4

Answer 1

Correct Question :

Find the zeroes of the polynomial _____ (x–2)^2 + 4.

Answer :

${(x - 2)}^{2} + 4 = 0\\ {x }^{2} - 4x + 4 = 0 \\ {x}^{2} - 2x - 2x + 4 = 0\\ x(x - 2) - 1(x - 2) = 0 \\ (x - 1)(x - 2) = 0$

This Gives :-

x - 1 = 0 and x - 2 =0

x = 1 and x = 2

Answer

The two zeros of polynomial (x – 2)^2+4 is 1 and 2 .