Question

Find the zeroes of the polynomial (x – 2)2 – (x + 2)2.​

Answer 1

Step-by-step explanation:

apply a^2-b^2 = (a+b)(a-b)

(x-2+x+2)(x-2-x-2)

(2x)(-4)

-8x

Answer 2

Answer:

Given

(x-2)² - (x+2)² = 0

Let us expand the following

(x-2)²= x² +4 -4x

(x+2)²=x²+4+4x

Let us substitute in given question

x²+4-4x -(x²+4+4x) =0

x²+4-4x -x²-4-4x = 0

cancel x² and 4

-8x = 0

x = 0/-8

x = 0

Hence zeros of polynomial of given question is 0

Check:

(x-2)²-(x+2)² =0

(0-2)² - ( 0+2)² = 0

(-2)²-(2)²=0

4-4 =0

0=0

Hence proved