find the zeroes of the polynomial (x-2)^2 - (x+3)^2
Answers
Answered by
4
(x-2)^2-(x+3)^2=0
=x^2-4x+4-(x^2+6x+9)=0
=x^2-4x+4-x^2-6x-9=0
=-2x-13=0
2x+13=0
x=-13/2
Similar questions