Question

find the zeroes of the polynomial x^2-3 and verify the relationship between the zeroes and the coefficient​

Answer 1

ANSWER

Given polynomial is x^2−3

Here, a=1,b=0 and c=−3x ^2−3=(x−3 )(x− 3 )

So, the value of x ^2 −3 is zero when x= 3

or x=−3

Threrfore , thr zeroes of x

2 −3 are 3 and − 3

.

Now, sum of zeroes =

3 − 3=0= 10 = a−b

product of zeroes =( 3 )(− 3 )=−3= 1−3 = ac

Hence verified.

Step-by-step explanation:

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