Question

Find the zeroes of the polynomial x^2 - 3 and verify the relationship
between the zeroes and the coefficients .​

Answer 1

Step-by-step explanation:

Recall the identity a² – b² =(a – b)(a + b). Using it,we can write:

x²-3=(x-√3)(x+√3)

So the value of x²-3 is zero when x=√3 or x=-√3

Therefore, the zeroes of x²-3 are √3 and -√3

Sum of zeroes =√3-√3=-3/1=-(Coefficient of x)/(Coefficient of x²)

Product of zeroes =(√3)(-√3)=(-3)/1 =(Constant term)/(Coefficient of x²)

Answer 2

Step-by-step explanation:

Recall the identity a² – b² =(a – b)(a + b). Using it,we can write:

x²-3=(x-√3)(x+√3)

So the value of x²-3 is zero when x=√3 or x=-√3

Therefore, the zeroes of x²-3 are √3 and -√3

Sum of zeroes =√3-√3=-3/1=-(Coefficient of x)/(Coefficient of x²)

Product of zeroes =(√3)(-√3)=(-3)/1 =(Constant term)/(Coefficient of x²)