Find the zeroes of the polynomial x^2 - 3 and verify the relationship
between the zeroes and the coefficients .
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Step-by-step explanation:
Recall the identity a² – b² =(a – b)(a + b). Using it,we can write:
x²-3=(x-√3)(x+√3)
So the value of x²-3 is zero when x=√3 or x=-√3
Therefore, the zeroes of x²-3 are √3 and -√3
Sum of zeroes =√3-√3=-3/1=-(Coefficient of x)/(Coefficient of x²)
Product of zeroes =(√3)(-√3)=(-3)/1 =(Constant term)/(Coefficient of x²)
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Answered by
59
Step-by-step explanation:
Recall the identity a² – b² =(a – b)(a + b). Using it,we can write:
x²-3=(x-√3)(x+√3)
So the value of x²-3 is zero when x=√3 or x=-√3
Therefore, the zeroes of x²-3 are √3 and -√3
Sum of zeroes =√3-√3=-3/1=-(Coefficient of x)/(Coefficient of x²)
Product of zeroes =(√3)(-√3)=(-3)/1 =(Constant term)/(Coefficient of x²)
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