Find the zeroes of the polynomial x^2+3 under root 5/2 x - 5 and verify the relationship
between its zeroes and coefficients.
Answers
Given : polynomial x² + 3√5/2 x - 5
To find : the zeroes of the polynomial
Solution:
x² + 3√5/2 x - 5
= x² +2√5x - √5 / 2 x - 5
= x(x + 2√5) - (√5 / 2 ) (x + 2√5)
= (x - √5 / 2)(x + 2√5)
zeroes are
√5 / 2 , - 2√5
Sum of Zeroes = √5 / 2 - 2√5 = - 3√5/2
Product of Zeroes = (√5 / 2)(-2√5) = -5
for ax² + bx + c
Sum of Zeroes = -b/a
Product of Zeroes = c/a
here a = 1 b = √5 / 2 c = -5
Sum of Zeroes = - 3√5/2
Product of Zeroes = -5
relationship between its zeroes and coefficients verified
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Answer:
polynomial x² + 3√5/2 x - 5
To find : the zeroes of the polynomial
Solution:
x² + 3√5/2 x - 5
= x² +2√5x - √5 / 2 x - 5
= x(x + 2√5) - (√5 / 2 ) (x + 2√5)
= (x - √5 / 2)(x + 2√5)
zeroes are
√5 / 2 , - 2√5
Sum of Zeroes = √5 / 2 - 2√5 = - 3√5/2
Product of Zeroes = (√5 / 2)(-2√5) = -5
for ax² + bx + c
Sum of Zeroes = -b/a
Product of Zeroes = c/a
here a = 1 b = √5 / 2 c = -5
Sum of Zeroes = - 3√5/2
Product of Zeroes = -5
relationship between its zeroes and coefficients verified
Learn More:
obtain all the zeros of the polynomial 8x^4+8x^3-18x^2-20x-5 if two ...
brainly.in/question/7286826
If two zeroes of a polynomial p(x) = x4 – 5x3 – x2 + 35x – 42 are 2 and
brainly.in/question/17304050
Step-by-step explanation: