Question

find the zeroes of the polynomial
-x^2+3x-1

Answer 1

Answer:

- (1 ± √5)/2

Step-by-step explanation:

Given polynomial = -x² + 3x - 1

a = -1, b = 3, c = -1

So, x = [-b ± √(b² - 4ac)]2a

x = {-(-1) ± √[(3)² - (4) (-1) (-1)]}/(2) (-1)

x = - [1 ± √(9 - 4)]/2

x = - (1 ± √5)/2