find the zeroes of the polynomial x^2-4x+3
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Answer:
Given, p(x)=x
2
−4x+3
=x
2
−3x−x+3
=x(x−3)−1(x−3)
=(x−3)(x−1)
For zeroes of polynomial, p(x)=0
i.e. (x−3)(x−1)=0
or, x=3 or x=1
Let, α=3 and β=1
α+β=
a
−b
αβ=
a
c
Here, a=1b=−4c=3
α+β=4
αβ=3
Step-by-step explanation:
hope it's helpful
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