find the zeroes of the polynomial x^2+x/6 -2.
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Answered by
23
x^2+x/6-2=0
=> 6x^2+x-12=0/6
=> 6x^2+9x-8x-12=0
=> 3x(2x+3)-2(4x+6)=0
=> (3x-2)(2x-3)(4x+6)=0
=> x=2/3 or -6/4
x= 2/3 and x= -3/2
=> 6x^2+x-12=0/6
=> 6x^2+9x-8x-12=0
=> 3x(2x+3)-2(4x+6)=0
=> (3x-2)(2x-3)(4x+6)=0
=> x=2/3 or -6/4
x= 2/3 and x= -3/2
Answered by
29
x²+x/6 -2 = 0
6x² + x - 12 = 0
6x² +9x - 8x -12 = 0
3x(2x+3) -4 (2x+3)
(3x-4)(2x+3)
x = 4/3 and x = -3/2
6x² + x - 12 = 0
6x² +9x - 8x -12 = 0
3x(2x+3) -4 (2x+3)
(3x-4)(2x+3)
x = 4/3 and x = -3/2
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