Question

Find the zeroes of the polynomial x– 2x – 80 and verify the relationship between zeroes and the coefficients.​

Answer 1

Answer:

Step-by-step explanation:

Let f(x) = x2 ˗ 2x ˗ 8

On factorizing by splitting the middle term we get

= x2 ˗ 4x + 2x ˗ 8

= x(x ˗ 4) + 2(x ˗ 4)

= (x ˗ 4) (x + 2)

To find the zeroes,

Let f(x) = 0,

then either (x ˗ 4) = 0 or (x+2) = 0 x = 4 or x = -2

Again, Sum of zeroes = -b/a = (-Coefficient of x)/(Coefficient of x2)

=(4 – 2) = 2

= 2/1

=2

Product of zeroes =c/a = Constant term / Coefficient of x2

= (4) (-2) = -8/1

=-8