Find the zeroes of the polynomial x 3 - 16x
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x³-16x=0
x(x²-16)=0
x=0 or x²-16=0
x²=16
x=+or- 4
therefore zeroes of the given polynomial are 0, -4, 4
x(x²-16)=0
x=0 or x²-16=0
x²=16
x=+or- 4
therefore zeroes of the given polynomial are 0, -4, 4
tarunsingh1:
You've typed zero as the zero of the polynomial which is false, a polynomial can equal to zero but zeros of polynomial are never zero
Answered by
1
Number of zeroes given polynomial is 3
Now x3-16x=0
Here x is common
So x (x2-16)=0
So x=0
And x2-16=0
Or
X2-(4)^2=0
(X+4)(x-4)=0
So x will be (-4)and 4
So required zeroes of that polynomial is 0,-4 and 4
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