Question

Find the zeroes of the polynomial x^3-3x^2-25x+75 if two zeroes are equal in magnitude but opposite in sign.

Answer 1

Answer:

zeros are 5 , -5 , -3

Step-by-step explanation:

GIVEN two zeros  are equal in magnitude and opposite sign

let they are  a and -a

then

x^3  - 3x^2 -25x +75 =[x+a] [x-a ] [ x +  b ]

                                 = [ x^2 - a^2 ] [ x +  b ]

                                 = x^3 + bx^2 - a^2 x  -  b a^2

so    b= -3  and  a^2 = 25  then a = 5 or -5

zeros are 5 , -5 , -3

Answer 2

Answer:

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