find the zeroes of the polynomial x^3-x
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If two zeroes are √2 and -√2so, the factor will be(x-√2)(x+√2) =0⇒x²-2=0
now, dividing the expression with this,
x²-2)x³+3x²-2x-6( x+3 x³ -2x - + +3x²-6 +3x²-6 - + 0 0
so,x³+3x²-2x-6= (x²-2)(x+3)
now, dividing the expression with this,
x²-2)x³+3x²-2x-6( x+3 x³ -2x - + +3x²-6 +3x²-6 - + 0 0
so,x³+3x²-2x-6= (x²-2)(x+3)
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