Question

Find the zeroes of the polynomial x^3 - x.


​

Answer 1

Answer:

0, 1, -1

Step-by-step explanation:

The zeroes of the polynomial are the values of x when p(x)=0

⇒ x  

3

−x=0

⇒ x(x  

2

−1)=0

⇒ x(x−1)(x+1)=0

⇒ x=0,1,−1  

Hence zeroes of p(x) are 0,1,−1.

Answer 2

Answer: x = 0, -1, 1

Step-by-step explanation:

$x^3 - x = 0\\x (x^2 - 1) = 0\\x(x+1)(x-1) = 0$

Now,

$x = 0; x+1 = 0; x-1 = 0\\x = 0, -1, 1$

Thanks. Please mark as brainliest...