find the zeroes of the polynomial x square - root 2x - 12
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Answered by
5
x^2 - √2x -12 = 0
x^2 -3√2x + 2√2x - 12 = 0
x (x - 3√2) + 2√2 (x - 3√2) = 0
(x - 3√2) (x + 2√2) = 0
x = 3√2 or x = - 2√2
Hope it helps.
x^2 -3√2x + 2√2x - 12 = 0
x (x - 3√2) + 2√2 (x - 3√2) = 0
(x - 3√2) (x + 2√2) = 0
x = 3√2 or x = - 2√2
Hope it helps.
Answered by
6
Answer :
Now, x² - √2x - 12
= x² - 3√2x + 2√2x - 12
= x (x - 3√2) + 2√2 (x - 3√2)
= (x - 3√2) (x + 2√2)
So, the zeroes of the given polynomial are
3√2 and (- 2√2)
#MarkAsBrainliest
Now, x² - √2x - 12
= x² - 3√2x + 2√2x - 12
= x (x - 3√2) + 2√2 (x - 3√2)
= (x - 3√2) (x + 2√2)
So, the zeroes of the given polynomial are
3√2 and (- 2√2)
#MarkAsBrainliest
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