Question

find the zeroes of the polynomial x square - root 2x - 12

Answer 1

x^2 - √2x -12 = 0

x^2 -3√2x + 2√2x - 12 = 0

x (x - 3√2) + 2√2 (x - 3√2) = 0

(x - 3√2) (x + 2√2) = 0

x = 3√2 or x = - 2√2


Hope it helps.

Answer 2

Answer :

Now, x² - √2x - 12

= x² - 3√2x + 2√2x - 12

= x (x - 3√2) + 2√2 (x - 3√2)

= (x - 3√2) (x + 2√2)

So, the zeroes of the given polynomial are

3√2 and (- 2√2)

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