Question

Find the zeroes of the polynomial x
$x { }^{2} - 4x - 32$
​

Answer 1

Answer:

Step-by-step explanation:

X²-4X-32

X²-8X+4X -32

X(X-8) +4(X-8)

(X-8) (X+4)

X - 8 = 0. or X+4 = 0

X = 8 or X = -4

Answer 2

${x}^{2} - 4x - 32 = 0 \: \: \: \ \: \: \: \: \: \: \: \: \: \\ {x}^{2} - 8x + 4x - 32 = 0 \: \: \: \:\\ x(x - 8) + 4(x - 8) = 0 \\ (x - 8)(x + 4) = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \\ x1 = 8 \: \: \: \: \: \: \: \: \: x2 = - 4 \: \: \: \: \: \: \: \:$

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