Question

find the zeroes of the polynomial x2-15x-34​

Answer 1

Answer:

Let p x = x 2 - 15 x - 34 Now , zeroes of p x are given by , p x = 0 ⇒ x 2 15 x - 34 = 0 ⇒ x 2 - 17 x + 2 x - 34 = 0 ⇒ x x - 17 + 2 x -

Answer 2

Answer:

${x}^{2} - 15x - 34$

${x}^{2} - (17 - 2)x - 34$

${x}^{2} - 17x + 2x - 34$

$x(x - 17) + 2(x - 17)$

$(x - 17)(x + 2)$

$(x - 17)(x + 2) = 0$

$(x - 17) = 0 \: and \: (x + 2) = 0$

$x = 17 \: and \: x = - 2$

17 and -2 are the zeros of the polynomial.

Ans. 17, -2

Hope it helps.