find the zeroes of the polynomial x2-17x+30
Answers
Answered by
8
Here is your answer!!!
x²-17x+30
=> x²-15x-2x+30
=> x(x-15) -2(x-15)
=> (x-2) (x-15)
=> x= 2 or 15
Hope it helps uhh!! ✌
Mark brainliest!!!
x²-17x+30
=> x²-15x-2x+30
=> x(x-15) -2(x-15)
=> (x-2) (x-15)
=> x= 2 or 15
Hope it helps uhh!! ✌
Mark brainliest!!!
Answered by
3
Hey buddy here's your answer.....
x^2 - 17x + 30 = 0
x^2 - (15 + 2)x + 30 =0
x^2 - 15x - 2x + 30 =0
x(x -15) - 2(x-15)=0
(x-2)(x -15) = 0
So,
x= 2
and, x= 15
Hope it helps......
x^2 - 17x + 30 = 0
x^2 - (15 + 2)x + 30 =0
x^2 - 15x - 2x + 30 =0
x(x -15) - 2(x-15)=0
(x-2)(x -15) = 0
So,
x= 2
and, x= 15
Hope it helps......
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