Question

find the zeroes of the polynomial x²_(✓2+1)x+✓2 and verify the relationship between the zeroes and coefficients of the polynomial

Answer 1

Answer:

x²-(√2+1)x+√2

x²-√2x-x+√2

x(x-√2)-1(x-√2)

x=1        x=√2

α⇒1        β⇒√2

α+β⇒1+√2               -b/a=-(-(1+√2)/1    =1+√2

α+β⇒-b/a

αβ⇒1×√2                  c/a = √2/1    =√2

αβ⇒c/a

Answer 2

Step-by-step explanation:

Do like this after this compare it with coefficients.