Question

find the zeroes of the polynomial x²-25 and verify the relation between the zeroes and the cofficent .​

Answer 1

Answer:

5 and -5 (±5)

Step-by-step explanation:

p(x) = x^2-25

Using factor theorem

Factors of 25 = ±5

Put x = 5 in p(x)

5^2-25

= 25 -25

=0 = 0

Therefore, 5 is a zero of p(x)

-5^2-25

= 25-25

=0 = 0

Therefore, -5 is a zero of p(x)

OR

p(x)=0

x^2 -25 =0

x^2=25

x = √25

x = ±5 or (5 and -5)

Zeros of p(x) are ±5 or (5 and -5)