Question

Find the zeroes of the polynomial x2

- √2x – 12​

Answer 1

We have,

f(x) = x2-√2x -12

Now, put f(x) = 0

x2-√2x –12 = 0

x2 - 3√2x + 2√2x – 12 = 0

x(x - 3√2) + 2√2(x - 3√2) = 0

(x - 3√2)(x + 2√2) = 0

x - 3√2 = 0 or x + 2√2 = 0

x = 3√2 or x = -2√2

So, the zeros of given polynomial are 3√2 and -2√2.