Question

find the zeroes of the polynomial x²-3​

Answer 1

Answer:

x²-3 = 0

x² = 3

x = ±√3

Step-by-step explanation:

Therefore, the zeroes of the given polynomial are √3 and -√3.

Relationship between the zeroes and coefficients:-

Sum of zeroes = √3+(-√3) = √3-√3

= 0 = -x coefficient/x² coefficient

Product of zeroes = (√3)(-√3)

= -(√3)² = -3/1 = constant/x² coefficient

Hope it helps

Answer 2

Answer:

Given polynomial is x 2 −3

Here, a=1,b=0 and c=−3

x 2−3=(x− 3 )(x− 3 )

So, the value of x 2−3 is zero when x= 3or x=− 3

Threrfore , thr zeroes of x 2 −3 are 3 and − 3 .

Now, sum of zeroes = 3 − 3 =0= 10 = a−b

product of zeroes =( 3 )(− 3 )=−3= −3/1 = c/a

Hence verified.