Question

find the zeroes of the polynomial x2-3 and verify the relationship between the zeroes and the coeffcients​

Answer 1

The given a polynomial

${x}^{2} - 3 = 0 \\ {x}^{2} = 3 \\ x = \frac{ - }{ + } \sqrt{3} \\ \alpha = - \sqrt{3} \\ \beta = \sqrt{3} \\ relation \: between \: zeroes \: and \: constant \\ \alpha + \beta = \frac{ - b}{a} \\ \sqrt{3} - \sqrt{3} = \frac{0}{1} \\ 0 = 0 \\ \alpha \beta = \frac{c}{a} \\ (\sqrt{3} ) \times ( - \sqrt{3} ) = \frac{ - 3}{1} \\ - ( \sqrt{3} \times \sqrt{3} ) = - 3 \\ - 3 = - 3answer$