Question

find the zeroes of the polynomial
x2–3 and verify the relationship between the zeroes and the coefficients
​

Answer 1

Answer:

Step-by-step explanation:

Given polynomial is x^2 −3  

Here, a=1,b=0  and c=−3

x^2 −3=(x−  3  )(x−  3 )

So, the value of x ^2 −3 is zero when x=  3  or x= −  3

Threrfore , the zeroes of x ^2  −3  are   3 and −3

​Now, sum of zeroes =  3  − 3  =0 =0/1  =   −b -a

​Product  of zeroes =(  3  )(−  3 )=−3= -3/1 = c/a  

 Hence verified.