Question

Find the zeroes of the polynomial x2 – 3 and verify the relationship between the zeroes and the coefficients.​

Answer 1

Step-by-step explanation:

Given polynomial is

$x2−3 </p><p></p><p>$

Here, a=1,b=0 and c=−3

$x2−3=(x−3)(x−3)$

So, the value of x^2−3 is zero when x= 3or

$x=−3</p><p>$

therefore, the

$zeroes of x2−3  are 3  and - \sqrt{3}$

Now sum of zeroes

$= \sqrt{3} - \sqrt{3} = 0 = \frac{0}{1} = \frac{ - b}{a}$

product of zeroes

$\sqrt{3} ( - \sqrt{3} ) = - 3 = \frac{ - 3}{1} = \frac{c}{a}$

hence verified