Question

find the zeroes of the polynomial x²-3and verify the relationship between the zeros and coeffients​

Answer 1

Answer:

Step-by-step explanation:

a=1                         b=0                       c=-3

$x^{2} -3$ = 0

$x^{2} - \sqrt{3x^{2} } = 0$

$(x -\sqrt{3} )(x -\sqrt{3} ) = 0$

$x =\sqrt{2} , x = \sqrt{-3}$

α=  √3                         β= -√3

α+β = √3 - √3  = $\frac{0}{1}$ =  $\frac{-b}{a}$

αβ = (√3)(-√3) = $\frac{-3}{1}$ = $\frac{c}{a}$

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