Question

Find the zeroes of the polynomial -x2+3x-2​

Answer 1

Answer:

-x²+3x-2

→ -x²+2x+1x-2

→ -x(x-2)+1(x-2)

→ (x-2)(-x+1)

→ x-2=0 -x+1 = 0

x=2,1

Step-by-step explanation:

therefore the zeroes are 2,1

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