Find the zeroes of the polynomial x2-5x-6 find the relationship between the coefficient and the zeroes of the polynomial
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Step-by-step explanation:
given,
polynomial = x²-5x-6
zeroes of the polynomial =( -b±√b²-4ac)/2a
x = ((-(-5)±√(-5)²-4(1)(-6)))/2
x =( 5±7)/2
so x is 6,-1
relation of zeroes and coefficients=?
sum of roots= - b/a
6+(-1)= -(-5)/1
5=5
product of zeroes= c/a
(6)(-1)= -6/1
-6=-6
so proved and verified
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