find the zeroes of the polynomial x2 +6x+9=0
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3
Answer:
Step-by-step explanation:
In the given polynomial x2−6x+9,
The first term is x2 and its coefficient is 1.
The middle term is −6x and its coefficient is −6.
The last term is a constant term 9.
Multiply the coefficient of the first term by the constant 1×9=9.
We now find the factor of 9 whose sum equals the coefficient of the middle term, which is −6 and then factorize the polynomial x2−6x+9 as shown below:
x2−6x+9=x2−3x−3x+9=x(x−3)−3(x−3)=(x−3)(x−3)
Therefore, x2−6x+9=(x−3)(x−3).
so the zero of the polynomial is 3.
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Step-by-step explanation:
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