Question

Find the zeroes of the polynomial X2-7 and verify the relationship between the zeroes and the coefficient

Answer 1

Answer:

Step by step solution

Perfect Solution for class 10 th

Answer 2

Concept Introduction:-

It could take the shape of a word or a numerical representation of a quantity's arithmetic value.

Given Information:-

We have been given that polynomial $X^2-7$

To Find:-

We have to find that the zeroes of the polynomial $X^2-7$ and verify the relationship between the zeroes and the coefficient

Solution:-

According to the problem

polynomial $X^2-7$

to find zero Equate the polynomial with zero

Hence $x^2 - 7 = 0\\\Rightarrow x^2 = 7\\\Rightarrow X=$±$7$

Hence zeroes are $+\sqrt7 , -\sqrt7$

$P(x) = ax^2+ bx + c$

Sum of zeros $= - b/a$

Product of zeroes$= c/a$

$X^2-7$ compare with $ax^2+ bx + c$

$a = 1 , b = 0 , c = -7$

Sum of zeroes $= - 0/1 = 0$

Sum of zeroes$= +\sqrt{7}- \sqrt{7} = 0$

Hence verified

Product of zeroes$= -7/1 = - 7$

Product of zeroes$= +\sqrt7 \times (-\sqrt7) = -7$

Final Answer:-

The correct answer is the relationship between the zeroes and the coefficient is verified.

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