find the zeroes of the polynomial x²+7x+10 and verify the relationship between the zeroes and the coefficient
Answers
Answered by
9
Step-by-step explanation:
x ( x + 5) + 2( x + 5)
(x + 2) ( x + 5)
x = -2 and x = -5
alfa + Bita = -b/a < => alfa × Bita = c/a
-2-5 = -7/1 -2 × -5 = 10
Hence, Verified
Answered by
42
Answer:
Given:
- p(x) = x² + 7x + 10
To do:
- Find the zeroes
- Verification
We can find the zeroes by simply factorising the polynomial
☘So factorising we get:
= x² + 7x + 10 = 0
= x² + 5x + 2x + 10 = 0
= x (x + 5) + 2 (x + 5) = 0
= (x + 5)(x + 2) = 0
= x + 5 = 0⠀⠀⠀⠀⠀⠀or⠀⠀⠀⠀⠀x + 2 = 0
= ⠀x = -5⠀⠀⠀⠀⠀⠀⠀or⠀⠀⠀⠀⠀⠀x = -2
So the zeroes are -5 , -2
☘Now verification:
⚕ For sum of zeroes , the relation used:
✮Putting the values:
➫
➫
⚕ For product of zeroes , the relation used:
✮Putting all the values:
➫
➫
_____________________________
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