find the zeroes of the polynomial x2-7x+12
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Answer:
the zeroes of the polynomial are +3 and +4
Step-by-step explanation:
In order to get the zeroes of the polynomial we need to equate the polynomial to zero
x^2-7x+12 = 0
x^2+(-3-4)x+12 = 0 [splitting the middle term -7x]
x^2-3x-4x+12 = 0
(x^2-3x)+(-4x+12) = 0
taking the common factors out, we get
x(x-3)-4(x-3) = 0
(x-3)(x-4) = 0
therefore equating to zero we get x=3 and x=4
hence the zeroes of the polynomial are 3 and 4
HOPE IT HELPS YOU
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