Question

. Find the zeroes of the polynomial x² + 8x + 6x.​

Answer 1

Answer:

$x = - 2 \: \: \: or \: \: \: x = - 4$

Step-by-step explanation:

${x}^{2} +6x + 8 = 0 \\ \\ {x}^{2} + 4x + 2x + 8 = 0 \\ \\ x(x + 4) + 2(x + 4) = 0 \\ \\ (x + 2)(x + 4) = 0 \\ \\ x = - 2 \: \: \: or \: \: \: x = - 4$