find the zeroes of the polynomial X2-9 and verify the relationship
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Find the zeros of the quadratic polynomial x2+9x+20, and verify the basic relationships between the zeros and the coefficients.
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ANSWER
Let p(x)=x2+9x+20=(x+4)(x+5)
So, p(x)=0→(x+4)(x+5)=0
∴x=−4 or x=−5
Thus, p(−4)=(−4+4)(−4+5)=0 and p(−5)=(−5+4)(−5+5)=0
Hence, the zeros of ( ) p x are -4 and -5 Thus, sum of zeros = -9 and the product of zeros 20 = (1)
From the basic relationships, we get
the sum of the zeros =−cofficientx2coefficient of x=19=−9 (2)
product of the zeros =cofficientx2constantterm=120=20 (3)
Thus, the basic relationships are verified
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