Question

Find the zeroes of the polynomial x2 - V2x – 12.
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Answer 1

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GIVEN :-

f( x ) = x² - √2x - 12

TO FIND :-

0 of Polynomial

SOLUTION :-

=> x² - √2x - 12 = 0

=>x² - 3√2x +2√x - 12 = 0

=>x(x-3√2)+2√2(x-3√2) = 0

=>(x+2√2)(x-3√2) = 0

So, -2√2 and 3√2 are the Zeros of the Given Polynomial