find the zeroes of the polynomial x²+⅙x-2
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Answer:
-4/3 and 3/2 !!
Step-by-step explanation:
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Given:
- We have been given a quadratic polynomial x² + ⅙x - 2.
To Find:
- We need to find the zeroes of this polynomial.
Solution:
The given polynomial f(x) is x² + ⅙x - 2.
We first need to multiply this equation by 6, we get
6x² + x - 12 = 0
Now, we can find the zeroes of this equation by the method of splitting the middle term.
We need to find two such numbers whose sum is 1 and product is -72.
So, two such numbers are 9 and -8.
=> 6x² + 9x - 8x - 12
= 3x(2x + 3) - 4(2x + 3)
= (2x + 3) (3x - 4)
Either 2x + 3 = 0 or 3x - 4 = 0.
When 2x + 3 = 0
=> 2x = -3
=> x = -3/2
When 3x - 4 = 0
=> 3x = 4
=> x = 4/3
Hence, zeroes of x² + ⅙x - 2 are -3/2 and 4/3.
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