Question

Find the zeroes of the polynomial X2

– X – 6 and verify the relation between the coefficients

and the zeroes of the polynomial.​

Answer 1

Answer:

${x} = 3 \: and \: {x} = - 2$

Step-by-step explanation:

${x}^{2} - x - 6$

$= {x}^{2} - 3x + 2x -6 \\ \\ = {x}({x} - 3) + 2({x} - 3)$

$({x} - 3)({x} + 2)$

$= > {x} = 3 \: \: and \: \: {x} = - 2$

Sum of zeroes = -b/a

$= \frac{ - ( - 1)}{1} \\ \\ = 1$

which is equal to sum of actual zeroes i.e,

3+(-2) = 1

Product of zeroes = c/a

$= \frac{ - 6}{1} \\ \\ = - 6$

which is equal to actual product of zeroes i.e,

$3 \times -2 = - 6$

Hence Proved

Hope this helps!!!!!

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