Question

find the zeroes of the polynomial x3-3x-10and verify the realtion between the zeros and coefficient
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Answer 1

Answer:

Refer above image.

Hope it's helpful!!!

Answer 2

Answer:

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x² - 3x - 10

x² - 5x + 2x - 10

x(x - 5) + 2(x - 5)

(x + 2)(x - 5)

if x + 2 = 0

∴ x = -2

if x - 5 = 0

∴ x = 5

∴ α = -2 and β = 5

verification ⇒

sum of zeroes ⇒ α + β = -b/a

-2 + 5 = -(-3)/1

3 = 3

LHS = RHS

product of zeroes

α.β = c/a

-2 × 5 = -10/1

-10 = -10

LHS = RHS

Step-by-step explanation: